-100x^2+55+3=50x^2-55x+23

Solution for -100x^2+55+3=50x^2-55x+23 equation:

-100x^2+55+3=50x^2-55x+23

We move all terms to the left:

-100x^2+55+3-(50x^2-55x+23)=0

We add all the numbers together, and all the variables

-100x^2-(50x^2-55x+23)+58=0

We get rid of parentheses

-100x^2-50x^2+55x-23+58=0

We add all the numbers together, and all the variables

-150x^2+55x+35=0

a = -150; b = 55; c = +35;
Δ = b2-4ac
Δ = 552-4·(-150)·35
Δ = 24025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24025}=155$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-155}{2*-150}=\frac{-210}{-300}
=7/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+155}{2*-150}=\frac{100}{-300}
=-1/3
$